Recent content by MrWarlock616

IMO, you shouldn't take his word. In the 2nd article, the author has little evidence for his reasoning, and there are no statements from Microsoft fully backing his claims. Even if they were true, I don't see how upgrading is a major problem. You will not have to pay for Windows updates, but...

If you're crazy about apps, go for Android. Windows phone is a good platform, just lagging in terms of apps. I suggest you make a list of the apps you care about the most -- the one's that are absolutely essential to you, and see if they're all available on the Windows phone store before buying...

That and ensure apps run on as many form factors as possible. I rarely use the start screen in 8.1. I always use the shortcut key Win + S when I want to launch an app. Using the start screen is difficult with a mouse, although they have tried to make it easy by making it scroll when the mouse...

Why would you hold back? They're offering a free upgrade for the first time, and having used Windows 10 via the Insider Preview, it's pretty great. They've listened to a lot of feedback from their Insider program and will continue to do so after the launch of Win 10. I use Windows 8 right now...

I recently got the Lenovo Ideapad Yoga 2 13, and it's working great so far! Best things about it are its HD screen, battery life and build quality. It's lightweight and I've used it for programming. I'm doing a CS course too.

Both Google Drive and OneDrive can be accessed via browsers, have you tried that?

Sorry I wrote 3 relations instead of 3 elements in the question. This problem has appeared twice in previous years exams. My gut tells me to use permutation and combinations but I've forgot most of it.

Homework Statement Show that if a set has 3 elements, then we can find 8 relations on A that all have the same symmetric closure. Homework Equations Symmetric closure ##R^* = R \cup R^{-1} ## The Attempt at a Solution If the symmetric closures of n relations are the same then...

From my book I've made many corrections to my last post

Easy way: Using that for scalar valued point function ∅ and a vector valued point function ##\vec{f}##, ##∇× (∅\vec{f}) = ∇∅ × \vec{f} + ∅ (∇ × \vec{f})## L.H.S. ## = ∇(\frac{1}{r^n}) × \vec{f} + ∅ (∇ × \vec{f}) ## ## = (-nr^{-n-2}\vec{r} ) × (\vec{a} × \vec{r}) + \frac{1}{r^n} (∇ ×...

I get it... r is not a constant. damn me

Homework Statement Prove that ##∇ × (\frac{\vec{a} × \vec{r}}{r^n})= \frac{2-n}{r^n}\vec{a}+\frac{n(\vec{a}.\vec{r}) \vec{r}}{r^{n+2}}## Nothing is mentioned about ##\vec{a}## so I'm assuming it is a constant vector. Also ##\vec{r} = <x, y, z> ## and ##|r|=r## Homework Equations...

Oh yeah. Thanks for the explanation though. I really never knew about this modulo 2^32 rule. I'm not going to refer to this book unless it's really necessary. The author hasn't explained himself properly. Definitely not a good book for a beginner like me.. Thank you D H, and the others!

That's an understatement for the education system in India. So, that means if there is ever an overflow in integer numbers, then the result will be the actual result modulo 2^32? Then what if I want the actual result?

No I know what it means, I just don't see how it applies here. I was never taught what you said