Recent content by MSG100

Ok, so I get: k=(4pi^2*m) / (T^2-t^2) and because Hooke's law says k = F/X (I'll use b as notation instead of X) F=mg so k=mg/b g = (4pi^2*b) / (T^2-t^2) How do I get the (H/L)-term into the equation? Have it something with Sin(x)=H/L so 1/Sin(x)=L/H to do?

I need some help with an equation. I will use to find the value of acceleration due to gravity. With a air track and a spring attached to a glider we should find the value of "g". The track is inclined and with two different equilibria (which are achieved by using two different masses on...

Yes, it's easy, I was outside with no pen or paper so I took some help from Wolfram. Math becomes hard when your in a hurry.

I made a mistake when I wrote it in Wolfram. Now I got it right!

Okay, if I do so I'll get: x^4-26x^2+25=0 and when I type it in Wolfram I get the solution: x=1 x=-1

I did it like this: Case 2: -(x^2-5)=4x Solution: x=1 Case 3: -(x^2-5)=-4x Solution: x=-1 Case 4: -(x^2-5)=4x Solution: x=-5

Case 2: 0 ≤ x < √5 x has to be positive. 0 or more, but less then √5 (here I'm not sure how to use the signs) Should it be -(x^2-5)=4x or (x^2-5)=-4x Both gives x=-5 and x=1

I usually write it as three intevals, but with this I can't do that.

They cross at x=-5, x=-1, x=1, x=5. Now I'm lost. The x^2 term makes it harder to get it right. Could someone show how this should be solved or make an exemple. I can't find any similar task with the x^2 term in it. I would be very grateful.

Of course, I meant "or" not "and" It's just x=5 that fit in case 1 In case 2 it's only x=-5 that fit. How do you make the assumptions?

I make a new attempt. I put the equation in two possible cases. Case 1: x^2-5=4x x^2-4x-5=0 x=5 and x=-1 Case 2: x^2-5=4(-x) x^2+4x-5=0 x=-5 and x=1

Solve |x^2-5|=4|x|. I tried to rewrite it as: (sqrt(x^2-5))^2=4*(sqrt(x))^2 Is this the right way to solve the equation?

Thanks, that makes sense! Then I just have following numbers k= 177, 178, 179, 180, 181 to make x and y positive and only k= 177, 179, 181 to make them positive AND odd.

Problem: Find all the positive integer solutions where x and y are odd numbers, to the equation: 17x+11y=1000 Attempt of solution: First attempt: With Diophantine equation have gotten the answers: x=2000 y=-3000 and the general solutions will be: x=2000-11k y=-3000+17k Now...

I understand. It's messy and hard to follow my calculations. Hopefully I will learn to write in latex soon. I don't have the answer but it seems too small, just 0.9 a.u.? Thanks a lot for the effort you put into helping people like me. Maybe someday we'll be the ones that help others!