Recent content by Mugen112
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Dot product - two points and a projection
Ah, caught my own mistake. I used the vector difference instead of the first vector. Thanks for all the help!- Mugen112
- Post #8
- Forum: Calculus and Beyond Homework Help
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Dot product - two points and a projection
Oh right, dot product is just one number. So I did the calculations, and I get.. (-2+3t, 3+2t) - (0,6) (dot) (3i+2j) = 0 (-2+3t, -3+2t) (dot) (3i + 2j) = 0 (-6+9t) + (-6+4t) = 0 (-12+13t)=0 t=12/13 ? So after I get t, I plug it back into (-2 + 3t, 3 +2t) ? I tried this and still get the...- Mugen112
- Post #7
- Forum: Calculus and Beyond Homework Help
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Dot product - two points and a projection
I can see the concept, but I don't understand how it would work. After I take the difference, I will be solving for t. There would be two equations with t correct? One for i and one for j? I tried this and got the wrong answer.- Mugen112
- Post #5
- Forum: Calculus and Beyond Homework Help
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Dot product - two points and a projection
Still not sure how to do the problem. Getting kind of frustrated. So the vector difference.. meaning ((-2+3t, 3+2t) - (0,6)) (dot) (3i+2j) = 0? Then solve for t?- Mugen112
- Post #3
- Forum: Calculus and Beyond Homework Help
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Dot product - two points and a projection
Homework Statement A person starts at coordinates (-2, 3) and arrived at coordinates (0, 6). If he began walking in the direction of the vector v=3i+2j and changes direction only once, when he turns at a right angle, what are the coordinates of the point where he makes the turn. Homework...- Mugen112
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- Dot Dot product Points Product Projection
- Replies: 8
- Forum: Calculus and Beyond Homework Help
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Undergrad Why does Physics have to be so hard?
I never said I knew what the best teaching method would be, but I can tell you that offering examples and not pure conception would help most students understand the material a little better. You can't argue with that, can you? I mean just like it math... you do a bunch of different problems so...- Mugen112
- Post #16
- Forum: Other Physics Topics
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Undergrad Why does Physics have to be so hard?
This was in no way meant to blame ANYONE! I know it looks like I'm blaming my professor, but all I was trying to say was that I think the class could be a little easier with a different teaching method. However, I just started this thread as a way for me to vent.. not blaming anyone. I'm sure...- Mugen112
- Post #14
- Forum: Other Physics Topics
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Undergrad Why does Physics have to be so hard?
yeah, I don't the professor doesn't know the material nor doesn't each it well, but almost everything he does is theory. No examples. Is this really how most Physics classes are?- Mugen112
- Post #8
- Forum: Other Physics Topics
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Undergrad Why does Physics have to be so hard?
I'm going to be doing a little venting in this thread so if you don't want to hear about it, click the back button. I'm in my second year of school right now. I'm in Physics 2 which is just basic calc based physics (second semester). I am in awe at how hard this class is. I'm sure most of...- Mugen112
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- Hard Physics
- Replies: 24
- Forum: Other Physics Topics
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Finding upper and lower bound superposition frequencies of ultrasound pulses
Homework Statement Ultrasound pulses of with a frequency of 1.000 MHz are transmitted into water, where the speed of sound is 1500m/s . The spatial length of each pulse is 12 mm. a) How many complete cycles are in each pulse? b) What is the lower bound of the range of frequencies must be...- Mugen112
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- Bound Frequencies Superposition Ultrasound
- Replies: 1
- Forum: Introductory Physics Homework Help
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Electron orbital frequency of hydrogen atom if given orbit radius
Ok, so.. I tried it again and it's still wrong. For V, I get 1583733 m/s with the equation that you gave me. V= sqrt (((9*10^9)((1.16*10^-19)^2)) / ((.053 * 10^-9)(9.11*10^-31)) = 1583733 m/s Then 2pi()R = 3.33*10^-10 D = RT 3.33*10^-10 / 1583733 = 2.1 * 10^-16 s so that's 1 revolution in...- Mugen112
- Post #3
- Forum: Introductory Physics Homework Help
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Electron orbital frequency of hydrogen atom if given orbit radius
Homework Statement In a classical model of the hydrogen atom, the electron moves around the proton in a circular orbit of radius 0.053 nm. A) What is the electron's orbital frequency? Homework Equations F = qE E= kq/r^2 angular velocity = v^2/r The Attempt at a Solution I'm...- Mugen112
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- Atom Electron Frequency Hydrogen Hydrogen atom Orbit Orbital Radius
- Replies: 6
- Forum: Introductory Physics Homework Help
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Light waves through grating. Min and Max measurements of wavelenghts in nm
Homework Statement Light passes through a 220 lines/mm grating and is observed on a 1.4m wide screen located 1.2m behind the grating. Three bright fringes are seen on both sides of the central maximum. What are the minimum and maximum possible values of the wavelength? Express your answers in...- Mugen112
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- Light Light waves Max Measurements Waves
- Replies: 1
- Forum: Introductory Physics Homework Help
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Distance between copper atoms in cubic crystal lattice
wow.. I've never been so stressed over homework. I want to break something =( . Anyway.. I emailed my prof... his response " You can use the atomic mass number to determine the mass of any given volume of copper. Once you do that, you can compute the number of atoms in that volume and then go...- Mugen112
- Post #2
- Forum: Introductory Physics Homework Help
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Distance between copper atoms in cubic crystal lattice
Homework Statement The atomic mass number of copper is A = 64. Assume that atoms in solid copper form a cubic crystal lattice. To envision this, imagine that you place atoms at the centers of tiny sugar cubes, then stack the little sugar cubes to form a big cube. If you dissolve the sugar, the...- Mugen112
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- Atoms Copper Crystal Crystal lattice Cubic Lattice
- Replies: 2
- Forum: Introductory Physics Homework Help