Recent content by munga

Thanks very much Stewart. It makes perfect sense now its morning. thanks for all your help. Munga

I'm not sure I am following this. If the angle the chain sinks to 15 degrees (even for both sides) and the persons weight is 80kgs then this is the formula as I understand it from above. T1 . sin(0) + T2 . sin(0) - Mg = Ma 15 . 0 + 15 . 0 - 80 -80 I am sure I am doing something wrong here as...

Thanks for your quick reply. I want to be able to calculate the tension or chain strength needed in kgs to support a persons weight sitting on a fence given the length and arc/radius of the chain. Each section of the chain linked fence is chain suspended between 2 posts, I would like to...

Hi, I'm hoping someone can show me a simple formula to calculate the tension or force on a chain fence with someone sitting on it. I imagine that the variables are; - the distance between the fence posts - the arc of the chain - the persons weight Thanks Munga