Recent content by mxam

Thanks. . . .

Thanks for your answers. I saw a "clear" solution online, let me show you:

((x^n-y^n)/x-y)=>\frac {x^1-y^1} {x-y}=>\frac {x-y} {x-y} OK Now, n= k x^k-y^k = m(x-y) ; where m is a positive integer. Now, my question is n=k+1 where, x^k+1+-y^k+1= ? I don´t understand the next step, i saw some explanations on internet but i don't understand ! Help me please. :s

I don't know how to prove by mathematical induction that x^n-y^n is divisible by x-y . . . Can you show me step by step? . . .Greetings!

I´ve 1 curious question: If i want to know what´s the correct serie for n^{n+1}, what´s the the procedure to follow?

Check the Attachment, the exercise says: "Demuestre por Induccion Matematica las siguientes preposiciones dadas" or in English, "Demonstrate by Mathematical Induction the following prepositions" . . . I think is a exercise that don't have a real solution, maybe the teacher´s proving us, . . ...

The teacher said that exist a solution, but with the opinions and the examples i think that he´s lying. . . =o!

A attach the picture of the book. . .

The Algebra Teacher gives the exercise, but i don't know, maybe don´t have a solution . . . ?

Can you help me with this exercise? 1^{1}+2^{2}+3^{3}+4^{4}+...+n^{n} = n^{n+1} Thanks! PD. I was trying to solve, and i have this: 1^{1}=1^{1+1} = 1 = 1 a) k^{k+1} b) k+1^{k+1} = k+1^{(k+1)+1} a in b) k^{k+1} + k+1^{k+1} = k+1^{(k+1)+1}...