Recent content by Myung

A = the cross-sectional area of material with area parallel to the applied force vector. A = Area of Hole(∏(1/2^2)/4) + Area of Thickness ( W = 1/8 , L = 1/2) F = 10353.98 N? Cross-sectional area is perpendicular to the Applied Force Vector while the Area of the Thickness is parallel to the...

A = ?? should I use the diameter or the thickness? or both? will that matter?

Homework Statement How much force is required to punch a hole ½ in. in diameter from a 1/8 in. thick steel sheet of shearing strength 4x104 psi. Homework Equations Shearing Modulus = Pressure/Shearing Strain Pressure = F/A Shearing Strain = DistanceSheared/Length-to-be-sheared...

Can you atleast explain to me the relationship of Shearing Strength to this equation and how I can use the value of the Strength of the object to get the force?

P/T = nR/V Let P/T = k k = nR/V Given the case that there are 1.10 moles in 26.2 dm^3/L of He k = [1.10moles ( 0.8206 ) L-Atm/moles-K] / 26.2L of He k = 0.03445267176 Atm/Kelvin Constant value gained! n = V/R * (k) n = 28.8 L / 0.8206 Litres-atm/mole-kelvin * (...

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Actually, I just got the formula from my book. It's a custom made book of my Professor in our University. Glad I can help.

Yep, Thats about it ;) Glad you understood the formulas. Remember to make your life easier: Sp.Gr.(Object) = Sp.Gr.(Fluid)*Weight of Object in Air / buoyant Force

Remember, You have the Specific Gravity of your Metal which is "3.57" Now the formula states that: Sp.Gr (Metal) = [Sp.Gr(Fluid)*(Weight in Air of Metal)] / buoyant Force Thus: 3.57 = [Sp.Gr(Fluid)*(Weight in Air of Metal)] / buoyant Force By Fluid I meant your unknown fluid which...

They are inversely proportional to each other ( P and T ) , Universal Gas Constant = 8.206 ( Litres - atm / mole - K ) n = PV/RT 1 atm is the constant Pressure at sea level but I don't know the temperature?

Yes, It is included in Archimedes Principle. But these formula are not present in all of the books that has his Principle. You got the density correct now how do you find the Density of the Oil? Read my previous post I edited it.

Homework Statement Blimps are being considered for use as freight carriers. A scale model rises when filled with helium to a volume of 55.0 dm3. When 1.10 mol He is added to the blimp, the volume is 26.2 dm3. How many more grams of He must be added to make it rise? Assume constant T and P...

You can actually get the density of the Metal using the Specific Gravity : Sp. Gr. = Weight in Air / buoyant Force or [W(in air) - W(in water)] Then another form of Specific Gravity is: Sp. Gr. = Density of Substance/ Density of Water Thus : Density of Substance = Sp.Gr / Density of Water...

So, 90% of it is only 233.82 We need the force to be 110% so it can match the output force which will be 285.78 N of force in the input ? Correct? (