Calculating Grams of Helium Needed for Blimp to Rise

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Homework Help Overview

The problem involves calculating the amount of helium needed for a blimp to rise, given specific volumes and moles of helium. The context is rooted in gas laws and the behavior of gases under constant temperature and pressure conditions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between pressure, volume, and temperature in the context of the ideal gas law. There are questions about how to express the number of moles as a function of volume while maintaining constant temperature and pressure.

Discussion Status

Some participants have provided guidance on grouping constants and finding a new constant to simplify the calculations. There is ongoing exploration of how to derive the necessary values from the given information, but no consensus has been reached on the final approach.

Contextual Notes

Participants note the assumption of constant temperature and pressure, and there are discussions about the implications of not knowing the exact temperature. The problem constraints and the specific values provided are under consideration as they work through the calculations.

Myung
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Homework Statement



Blimps are being considered for use as freight carriers. A scale model rises when filled with helium to a volume of 55.0 dm3. When 1.10 mol He is added to the blimp, the volume is 26.2 dm3. How many more grams of He must be added to make it rise? Assume constant T and P. (4.003 g He = 1 mol He)

Homework Equations



PV = nRT
R = 0.8206 ( litres-atm/mole-K )
1 dm^3 = 1L

The Attempt at a Solution



Required volume to fill is 28.8 dm^3 or L

PV = nRT

Assume T and P is constant?
How do we do that? That is my question.
 
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Myung said:

Homework Statement



Blimps are being considered for use as freight carriers. A scale model rises when filled with helium to a volume of 55.0 dm3. When 1.10 mol He is added to the blimp, the volume is 26.2 dm3. How many more grams of He must be added to make it rise? Assume constant T and P. (4.003 g He = 1 mol He)

Homework Equations



PV = nRT
R = 0.8206 ( litres-atm/mole-K )
1 dm^3 = 1L
You are trying to find n. You want to express n as a function of V. If P and T are constant, what is the relationship? How would you find P/RT (which is constant) from the information provided?

AM
 
Andrew Mason said:
You are trying to find n. You want to express n as a function of V. If P and T are constant, what is the relationship? How would you find P/RT (which is constant) from the information provided?

AM

They are inversely proportional to each other ( P and T ) ,

Universal Gas Constant = 8.206 ( Litres - atm / mole - K )

n = PV/RT

1 atm is the constant Pressure at sea level but I don't know the temperature?
 
bump!
 
Myung said:
They are inversely proportional to each other ( P and T ) ,

Universal Gas Constant = 8.206 ( Litres - atm / mole - K )

n = PV/RT

1 atm is the constant Pressure at sea level but I don't know the temperature?

You don't need to know the pressure or temperature; It's enough to know that they are constants.

In your expression for n above, group all the constants together and replace them by a single new constant. Let's call it k. Now, in the problem statement you're given a particular case for n and V. Find k from that particular case. You can then use this k value to proceed.
 
gneill said:
You don't need to know the pressure or temperature; It's enough to know that they are constants.

In your expression for n above, group all the constants together and replace them by a single new constant. Let's call it k. Now, in the problem statement you're given a particular case for n and V. Find k from that particular case. You can then use this k value to proceed.

P/T = nR/V

Let P/T = k

k = nR/V

Given the case that there are 1.10 moles in 26.2 dm^3/L of He

k = [1.10moles ( 0.8206 ) L-Atm/moles-K] / 26.2L of He

k = 0.03445267176 Atm/Kelvin

Constant value gained!

n = V/R * (k)

n = 28.8 L / 0.8206 Litres-atm/mole-kelvin * ( 0.03445267176 Atm/Kelvin )

n = 1.21 moles

1 mole = 4.003 g HE

He = 4.84 Grams.

THANKS!
 

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