Recent content by naffin
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Graduate Question about the Mach-Zehnder experiment
So the quantum mechanical description should be this one: if we start sending lots of photons at a time, the first of them will be detected with a probability of 50% on each detector because of the large difference in the two "possible paths", while the others will interfere among them producing...- naffin
- Post #4
- Forum: Quantum Physics
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Graduate The electric dipole approximation
In a first approximation we can ignore the quantity \vec{k} \cdot \vec{x} = \frac{2 \pi}{\lambda} \hat{k} \cdot \vec{x} because EM-induced atomic transitions involve radiation of length \approx 10^{3} angstroms, and the integral is essentially in a domain with a characteristic length of 1...- naffin
- Post #2
- Forum: Quantum Physics
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Graduate Question about the Mach-Zehnder experiment
Question about the Mach-Zehnder interferometer experiment Let's consider a Mach–Zehnder interferometer with a significant difference in length between the two physical paths. The optical paths are set up such that the two beams interfere 100% destructively on one of the two detectors. What...- naffin
- Thread
- Experiment
- Replies: 5
- Forum: Quantum Physics
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Graduate Heisenberg Picture: Popularity & Photon Double-Slit Treatment
From Wikipedia - "Heisenberg picture" : "By the Stone-von Neumann theorem, the Heisenberg picture and the Schrödinger picture are unitarily equivalent." As far as I know that theorem proves the equivalence between Heisenberg matrix representation and Schrödinger wave representation, time...- naffin
- Post #4
- Forum: Quantum Physics
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Graduate Why do we assume unitary evolution?
All my divagation was essentially due to the evolution aspect of a system (the parameter b), which somehow separates the time translational symmetry from the others, while Francesco's argument was about treating space and time on equal footing. I don't know anything about black holes, but (for...- naffin
- Post #26
- Forum: Beyond the Standard Models
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Graduate Why do we assume unitary evolution?
In my frame of reference I describe a particle with a function | \psi(t) \rangle . Let's focus on a precise time t_0 , for example when the particle changes its color; actually in quantum mechanics you see the color only by measurement, in this sense it is a 'classical' example: I'm not...- naffin
- Post #25
- Forum: Beyond the Standard Models
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Graduate Why do we assume unitary evolution?
I've seen that conservation of transition probabilities is often interpreted as conservation of information or entropy. An interesting accessible paper for example is: http://arxiv.org/abs/quant-ph/0407118- naffin
- Post #23
- Forum: Beyond the Standard Models
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Graduate Why do we assume unitary evolution?
Uhm, the operator U_{s}(t) that I am using is different than Weinberg's, and I was assuming |b \rangle as an arbitrary time-indipendent vector. Anyway I realize that using time-indipendent vectors in my previous example was obscuring the main idea, so I try to be more clear. In my reference...- naffin
- Post #22
- Forum: Beyond the Standard Models
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Graduate Why do we assume unitary evolution?
The difference between space and time is that a system evolves with time, not with space. I think I've found a nice way to explain what I was trying to say: in a given frame of reference we describe a system with a trajectory in the space of states \psi(t) . It seems obvious to me that in any...- naffin
- Post #20
- Forum: Beyond the Standard Models
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Graduate Why do we assume unitary evolution?
A transformation between states (rays) is implementable by a unitary operator if and only if it is one-to-one and preserves transitions probabilites. Let's focus on the Schrödinger picture: at a certain time t we describe a system configuration with a vector \psi . The obvious thing to say...- naffin
- Post #18
- Forum: Beyond the Standard Models
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Graduate Why do we assume unitary evolution?
I think that Weinberg's derivation is misleading because he assumes a priori unitary evolution using the Heisenberg picture, in which states don't evolve in time, so the probability transitions are trivially constant. In the Schrödinger picture if we look at a system at time t in a...- naffin
- Post #15
- Forum: Beyond the Standard Models
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Graduate Why do we assume unitary evolution?
Does someone have any proof ? I think we have to make other assumptions.- naffin
- Post #13
- Forum: Beyond the Standard Models
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Graduate Measuring orbital angular momentum
I'd like to know an example, too.- naffin
- Post #3
- Forum: Quantum Physics
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Graduate Axiomatic derivation of [X,P]?
True, we know also that \left[ Q_{\alpha},P_{\beta} \right] = i \delta_{\alpha \beta} , but we don't know yet what is the group generated by Q (from a physical point of view). I've read App.4,5 and Ch.4, but without knowing the meaning of the group generated by Q I can't see how to...- naffin
- Post #20
- Forum: Quantum Physics
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Graduate Why isn't momentum a function of position?
Ballentine, pag. 89. For the exact solution I know "Quantum Mechanics I", Galindo-Pascual. In general they are just unitary operators, I don't know other structures.- naffin
- Post #50
- Forum: Quantum Physics