Recent content by NapoleonZ
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A PDE I can't solve by seperation of variables
Yes, they are.- NapoleonZ
- Post #3
- Forum: Calculus and Beyond Homework Help
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A PDE I can't solve by seperation of variables
Homework Statement Homework Equations After simplification, the PDE is (b^2/a^2)(d^2 v/ d x^2) + (d^2 v/ d y^2) = -1 The Attempt at a Solution Obviously, it can't be solved by separation of variables. And I also failed in similarity solution.- NapoleonZ
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- Pde Seperation of variables Variables
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Laplace equation in polar coordinate
i] I'm confused too. ii] No always, actually D=-C*a^(2n)- NapoleonZ
- Post #5
- Forum: Calculus and Beyond Homework Help
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Laplace equation in polar coordinate
I have got two sets of solutions U(r,θ)=A*ln(r)+B* U(r,θ)=(C*r^λ+D/r^λ)*(E*sinλθ+F*cosλθ) My problem is the boundary conditions are nonhomogeneous, with which I cannot work out the coefficients.- NapoleonZ
- Post #3
- Forum: Calculus and Beyond Homework Help
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Laplace equation in polar coordinate
Urr+(1/r)*Ur+(1/r^2)*Uθθ=0 a<r<b, 0<θ<w with the conditions U(r,0)=U1 U(r,w)=U2 U(a,θ)=0 U(b,θ)=f(θ)- NapoleonZ
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- Coordinate Laplace Laplace equation Polar
- Replies: 4
- Forum: Calculus and Beyond Homework Help