Laplace equation in polar coordinate

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 4K views
NapoleonZ
Messages
6
Reaction score
0
Urr+(1/r)*Ur+(1/r^2)*Uθθ=0

a<r<b, 0<θ<w

with the conditions
U(r,0)=U1
U(r,w)=U2
U(a,θ)=0
U(b,θ)=f(θ)
 
Physics news on Phys.org
Welcome to PF!

Hi NapoleonZ! Welcome to PF! :smile:
NapoleonZ said:
Urr+(1/r)*Ur+(1/r2)*Uθθ=0

a<r<b, 0<θ<w

with the conditions
U(r,0)=U1
U(r,w)=U2
U(a,θ)=0
U(b,θ)=f(θ)

Show us what you've tried, and where you're stuck, and then we'll know how to help. :smile:
 
I have got two sets of solutions

U(r,θ)=A*ln(r)+B*
U(r,θ)=(C*r^λ+D/r^λ)*(E*sinλθ+F*cosλθ)

My problem is the boundary conditions are nonhomogeneous, with which I cannot work out the coefficients.
 
NapoleonZ said:
I have got two sets of solutions

U(r,θ)=A*ln(r)+B*
U(r,θ)=(C*r^λ+D/r^λ)*(E*sinλθ+F*cosλθ)

My problem is the boundary conditions are nonhomogeneous, with which I cannot work out the coefficients.

Hi NapoleonZ! :smile:

i] I'm a little confused about the conditions … U(a,θ)=0 seems incompatible with U(r,0)=U1
and U(r,w)=U2, if the conditions are continuous

ii] Doesn't the condition U(a,θ)=0 make it fairly clear what E and F are (unless λ = 0)?
 
tiny-tim said:
Hi NapoleonZ! :smile:

i] I'm a little confused about the conditions … U(a,θ)=0 seems incompatible with U(r,0)=U1
and U(r,w)=U2, if the conditions are continuous

ii] Doesn't the condition U(a,θ)=0 make it fairly clear what E and F are (unless λ = 0)?


i] I'm confused too.
ii] No always, actually D=-C*a^(2n)