Recent content by nazmulhasanshipon

Someone pointed that the energy lost by the battery is ##V=\frac{Qd}{\epsilon A}## (because the electric potential difference would be used to to raise the potential difference between the plates) and energy gained by the capacitor is ##E=\frac{1}{2}QV##. And therefore they are different. But I...

Imagine the two terminal of a *parallel-plate capacitor* are connected to the two terminal of a battery with electric potential difference #V#. If the capacitance of the capacitor is #C#, and the area of each plate is $A$. In this process would the energy lost by the battery and the stored...

Sir, if I haven't made a mistake then the change in entropy for the isobaric process is- $$n C_v \int_{T_1}^{T_2} \frac{dT}{T} + nR \ln \left (\frac{V_2}{V_1} \right )$$ and the change in entropy in the isothermal process is $$nR \ln \left (\frac{V_2}{V_1} \right )$$ Am I correct, sir?

I will be doing it the ways you described. I'm sure I'll face some problem. Can I know when would you be free?

Okay, sir. Then the next step?

Yes, ##\ln \frac{T_2}{T_1}## is the integral. But the problem is that in Calculus teacher told that ##dx, dy## has no meaning and ##\frac{dy}{dx}## is not a fraction so we can't separate them.

Yes, sir. It's a wonderful explanation. So far, it makes sense. But the symbol ##dT## makes me to think it is a differential.

So, sir ##dT## means little change in between temperature ##T_1## and ##T_2##? I thought that was a differential. (and sorry I didn't call you sir earlier, I didn't know you were a teacher)

and also sir, can you please tell me what is 2nd law of thermodynamics using the definition of entropy?

Actually I don't know about the equation of the entropy change case in constant volume. Would you tell me?

I know the change in entropy is ##\cfrac{\Delta Q}{T}##. And I don't need it for the constant volume. I need it for the constant pressure.

We can use Charles law to find out the final temperature. And "what is the equation for the change in entropy between the two states?" I don't know about that. Please help me understand it.

Upon seeing the question in my assignment I knew in a isobaric process, work done by the gas is ##W=P\Delta V## so if volume is increased ##4## times the original considering the original volume as ##V## we can say after expansion the volume is ##4V##. Then ##W=P(4V-V)=3PV## and the ##Q## would...

is it ##F=\cfrac{mv^2}{r}## @haruspex ?

@kuruman, I think it's the centripetal force ##\frac{mv^2}{r}##.