Recent content by nchin

thanks guys. my prof likes to be as vague as possible and not give me the UTS value.

-0.001 = 24.002" (4.8 x 10^-6)(Tf - 80) Tf = 71.32 F

-0.001 = 23.998" (4.8 x 10^-6)(Tf - 80) Tf = 71.32 F thanks!

Laser mill, water jet mill, drill/file?

What are three different ways that i can produce a hole with a square cross section in a plate with a thickness of at least 1"?

thermal expansion = .001? 0.001 = 24.002" (4.8 x 10^-6)(Tf - 80) Tf = 88.679? 0.001 = 23.998" (4.8 x 10^-6)(Tf - 80) Tf = 88.33?

0.003 = 23.997" (4.8 x 10^-6)(Tf - 80) Tf = 106.04 0.003 = 24.003" (4.8 x 10^-6)(Tf - 80) Tf = 106.038 0.002 = 24.002" (4.8 x 10^-6)(Tf - 80) Tf = 97.3597 0.002 = 23.998" (4.8 x 10^-6)(Tf - 80) Tf = 97.3625 so the range would be from 97 F - 106 F?

oh yea my mistake. i meant tensile stress = 1000/A = 55,059 psi. i looked it up and i found 40,000 psi for ultimate tensile stress of steel stranded wire. is that correct?

Homework Statement A cable containing 37 strands of 0.0250" diameter steel wire successfully supports 1000 lb load in tension. Calculate tensile stress? Do you think this is a reasonable and safe design stress level?Homework Equations tensile stress = F/A The Attempt at a Solution A = [...

so do i make two calculations? One with initial length as 24 + 0.002 and the other 24 - 0.002?

Homework Statement A 24" diameter titanium jet engine disk is machined to tolerance or +/- 0.002". Customer will accept +/- 0.003". The part is machined and measured in you plant at 80F. What is the max temp range for the customer to measure the part which you should specify in the contract...

Couple moment problems -- Calculate the distance? Homework Statement http://imageshack.com/a/img691/1734/804i.jpg Homework Equations M = F x d The Attempt at a Solution M = Fxd 20Nm = 35N*x x = 0.57m cos 30 deg = x/d d = x/cos 30 deg = 0.57m/cos 30 deg = 0.66m...

Homework Statement What are the bifurcation values for the equation: dy/dt = y^3 +ay^2 Homework Equations The Attempt at a Solution Equilibrium solutions: y^3 + ay^2 = 0 ==> y^2 (y + a) = 0 ==> y = 0 (double root), or y = -a. a = 0 is the sole bifurcation point, since...

Homework Statement dy/dt = -4t+2 y(0) = 1 find y(1)=? Homework Equations The Attempt at a Solution so first i solve the diff equation: dy/dt = -4t + 2 dy=(-4t+2)dt ∫dy=∫(-4t+2)dt y(t) = -2t^(2)+2t+C y(0)=1 1=-2(0)^(2)+2(0)+C_1 1=C_1 y(t) = -2t^(2)+2t+1 now i solve...

what did you make that A variable equal to?