1. The problem statement, all variables and given/known data A 24" diameter titanium jet engine disk is machined to tolerance or +/- 0.002". Customer will accept +/- 0.003". The part is machined and measured in you plant at 80F. What is the max temp range for the customer to measure the part which you should specify in the contract? 2. Relevant equations Delta L = L initial (alpha)(Tf - Ti) [alpha = coefficient of thermal expansion] 3. The attempt at a solution 0.003 = 24" (4.8 x 10^-6)(Tf - 80)--->Tf = 106 F?? I dont think its this simple. Im pretty sure im wrong. help please!