Recent content by neilparker62
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Prove that ## 4\tan^{-1}\left[\dfrac{1}{5}\right]- \tan^{-1}\left[\dfrac{1}{239}\right]= \dfrac{π}{4}##
"All in one" derivation of compound angle formulae - based on the video construction.- neilparker62
- Post #21
- Forum: Precalculus Mathematics Homework Help
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Prove that ## 4\tan^{-1}\left[\dfrac{1}{5}\right]- \tan^{-1}\left[\dfrac{1}{239}\right]= \dfrac{π}{4}##
Neat geometric derivation of ##\tan(A+B)=\frac{\tan A + \tan B}{1-\tan A \tan B}## if we divide all terms in ##\frac{ay+bx}{by-ax}## by ##by##.- neilparker62
- Post #20
- Forum: Precalculus Mathematics Homework Help
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Prove that ## 4\tan^{-1}\left[\dfrac{1}{5}\right]- \tan^{-1}\left[\dfrac{1}{239}\right]= \dfrac{π}{4}##
$$\tan x=\frac{1}{5} \implies \tan2x=\frac{5}{12} \implies \tan4x=\frac{120}{119}$$ $$\tan \left( \tan^{-1} \left( \frac{1}{239} \right)+\frac{\pi}{4}\right)=\frac{1+\frac{1}{239}}{1-\frac{1}{239}}=\frac{120}{119}$$- neilparker62
- Post #17
- Forum: Precalculus Mathematics Homework Help
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It will highlight your solution as well as illustrate a treasure trove of underlying geometry...
It will highlight your solution as well as illustrate a treasure trove of underlying geometry 'dug up' by AI. I will include an introductory paragraph saying I'm writing it as a reference example for the many contributions you have made on PF.- neilparker62
- Profile post comment
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Ok - so what I was thinking of doing is writing a short article on one of your many interesting...
Ok - so what I was thinking of doing is writing a short article on one of your many interesting posts and subsequent threads. https://www.physicsforums.com/threa...riangle-given-some-extra-information.1063874/- neilparker62
- Profile post comment
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Hi again. I don't think there is anything like an "official" pf letterhead since it's just a...
Hi again. I don't think there is anything like an "official" pf letterhead since it's just a website. But you can check with @Greg Bernhardt on that one.- neilparker62
- Profile post comment
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Hi. Did you get your reference from someone on PF ? I can write something like I see you...
Hi. Did you get your reference from someone on PF ? I can write something like I see you regularly posting interesting Maths/geometry problems and contributing to discussions around those.- neilparker62
- Profile post
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Doppler effect: why do I find this exercise so difficult?
Thanks for the link.- neilparker62
- Post #6
- Forum: Introductory Physics Homework Help
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Hi everyone
I'm sure they don't and wouldn't worry much if they did! I wish I was more clued up on those particular topic areas but in all honesty I'm not.- neilparker62
- Post #8
- Forum: New Member Introductions
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Hi everyone
Welcome to the PF community - I'm sure you'll find some expert advice on those topic areas (not that I personally know much about them!)- neilparker62
- Post #6
- Forum: New Member Introductions
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Paul Hinds has passed
Deepest condolences - Robert to you and all the family. It's been an honour to share this forum with stalwarts such as your Dad. We'll hugely miss his always sage and thoughtful posts.- neilparker62
- Post #29
- Forum: Feedback and Announcements
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Praise 2024 Member Award Ceremony
Seconded. And if I may put it this way - it's reward enough to be part of the PF community and (occasionally) to post something that others find useful/interesting . Or to start a thread which usually yields any number of useful responses.- neilparker62
- Post #11
- Forum: Feedback and Announcements
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Member and Mentor Appreciation Thread
@PeroK . Stop complaining about AI - you're better by far!- neilparker62
- Post #4
- Forum: Member Awards 2025 Archive
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Undergrad Trigonometry problem of interest
Yes - as mentioned above the technique is strikingly similar to that employed in Diophantus II VIII which is "to divide a square into two other squares" - I take the liberty of copy/pasting the image from Wikipedia which illustrates the technique when the given square is 16. y=mx-4 is...- neilparker62
- Post #78
- Forum: General Math
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Undergrad Trigonometry problem of interest
Perhaps worth noting (in retrospect) that you will get this equation directly by implementation of @GiorgioPastore 's suggestion in post #73. Very interesting discussion on parameterization of this problem. Am still trying to get my head round some of those posts! See also...- neilparker62
- Post #76
- Forum: General Math