Recent content by NemoMnemosyne

Yes I can. I ended up getting... \LARGE M_r(gsin{\theta_r} - a) = M_lgsin{\theta_l} + M_la If divide by the gsin{\theta_r} - a the answer still comes out negative for me. Am I right in thinking that if I reversed the order of... gsin{\theta_r} - a it would make it...

I seem to be having trouble figuring out how you get a positives on both sides of the equation above. I managed to get there but I had a negative the left side of it, (right-hand side of the problem). I'll write down all my steps... \LARGE T - M_lgsin{\theta_l} = M_la \LARGE...

You think I could get you to run through how you managed to get that? I still just can't see how you managed to get Mr by itself. I can tell there's some factoring in there somewhere but I guess I'm just not making the right calculations.

Yes the pulley is negligible, as is the rope. I drew a picture and free-body diagram and labeled all the forces accordingly. I think my issue here is figuring out how to do the algebra correctly to end up with the Mass of the right-hand side by itself so I can solve the problem. Anywhere in...

Homework Statement Suppose the angles on an inclined plane are 60*(left-hand side) and 20* (right-hand side). If the left-hand mass is 2.1 kg, what should the right-hand mass be so that it accelerates downslope at 0.64 m/s/s? Homework Equations F=ma The Attempt at a Solution...

This was an even numbered problem from the book so there are no answers to make sure I've done this correctly or not. Homework Statement An arrow fires horizontally at 41 m/s travels 23 m horizontally. From what height was it fired? Vi = 41 m/s a = g = -9.8m/s x = 23m Homework...