Recent content by neuro.akn

I am seeking information regarding mental health. I am wondering if there is a mental illness, disorder, syndrome, etc. that is characterized by persistent arguing/fighting? Is there an adult version or form of the oppositional defiant disorder? Almost as if the individual is addicted to arguing...

Thank you.

Hi, I'm just wondering why, chemically, acetone will stain plexiglass (Plexiglas) rather than cleaning it? Thanks in advance.

Okay, yes! I figured it out last night. The width and the height will be equal. Thank you, Tanya Sharma, besulzbach, and Mark44! Therefore, since V = 60cm^3 then w = 2 cm and h = 2 cm and thus l = 15cm

Wow. How about you specify more clearly like you just did first, that way I understand exactly what you are asking the first time. Anyway, l = 13cm + w Correct?

I did. A = lw and V = lwh

A = lw and V = lwh

Okay, I understand what you meant by that now; it makes sense that one cannot have l equal to a comparison. I'm unsure of determining l3 from the square property though.

They are different indeed. However, the length is 13cm GREATER THAN the width. It makes sense both ways, but saying the length is 13cm > the width is much easier to understand (for me anyways). Secondly, in terms of sides of a square, the property is that they are equal side lengths. But where...

That's all there is. The only other thing really is that it states the box has square ends.

Homework Statement A box has a length that is 13cm longer than its width, and the volume of the box is 60cm^3. Determine the dimensions of the box. Homework Equations V = lwh l = 13cm > w h = ? The Attempt at a Solution Since V = lwh, 60cm^3 = lwh and, l = 13cm > w w...

When you multiply (2x-7)*2(pi), you get -10x. Consider: (2x-7)*2(pi) = 4(pi)x - 14(pi) = -10x

Here is how I am solving: (2x-7)*2(pi)r = 16(pi)x^2 - 68(pi)x + 42(pi) I divide each side by (2x-7)*2(pi) but this expression (2x-7)*2(pi) simplifies into -10x. So I will proceed to long divide 16(pi)x^2 - 68(pi)x + 42(pi) by -10x ?

I'm not sure how I would solve for the radius, even though what you said makes sense.

Thank you! This is starting to make sense now, but what would I then need to do with the equation given for the area of the can?