Recent content by Newton25

Yes, that would help. Thank you. I wasn't sure if I was able to ignore it or not. So, would the Q then be equal to ([.00100]^4 * [antilog(-5.00)]^4)/ ([.50]^2 * [1.50]^4) ?

< Mentor Note -- thread moved to HH from the technical chemistryforum, so no HH Template is shown >[/color] I was given this problem: A voltaic sell uses the reaction 4Fe3+ + H2 --> 2Fe2+ +2H+. Find the cell potential when [Fe3+]=1.50 M, PH2=.50 atm, and [Fe2+]=.00100 M and the pH of both anode...