Yes, that would help. Thank you. I wasn't sure if I was able to ignore it or not.
So, would the Q then be equal to ([.00100]^4 * [antilog(-5.00)]^4)/ ([.50]^2 * [1.50]^4) ?
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I was given this problem:
A voltaic sell uses the reaction 4Fe3+ + H2 --> 2Fe2+ +2H+.
Find the cell potential when [Fe3+]=1.50 M, PH2=.50 atm, and [Fe2+]=.00100 M and the pH of both anode...