i'm sorry but it's hard to understand that, thanks for the help.
i didn't understand that sentence . you mean "you are not accelerating" but i do feel that forces are exert upon me then of course i feel that i accelerate ? no?
but in inertia frame i have acceleration up and the body slides on...
can you tell me if there is another way? because i never solved problems with that technique and i don't understand why to add a force in the opposite way if the eleveator accelerates upward.
edit: you say that if I am in an elevator and it starts to accelerate then by Newton first law my body...
i stuggle with the question of the inclined plane in accelerating elevator. he told me what i would do if the angle was 0 .
i saw in some threads that you need to put another F equals to ma even though the object doesn't feel that F force but i don't understand that.
thanks a lot man, i think i get the idea of this problems.
can you give me direction on how to put the x and y-axis on the second problem with the elevator ?
\begin{aligned}\sum F_{my}=0\\ N-my=0\\ N=mg\\ f_{s}=\mu_{s} N=\mu _{s}mg\end{aligned}
that on the upper block m.
so in the x Axis of M
\begin{aligned}\sum F_{Mx}=Ma\\ F _{min}-f_{s\max}=M_{a}\\ F_{min}=\mu_{s}mg+M\mu_{s}g\\ F_{min}=\mu_{s}g\left(m+M\right) \end{aligned}
is it correct?
hello , thanks for the help.
when i wrote "the two blocks wIl move as 1 " and you showed me that the solution i found refutes this claim,
i have a question about how it could be that F would be equal to fsmax and that doesn't cause the little case m to change it's state to kinetic friction...
hello, thanks for the reply and i hope you understand me , english isn't my native language .
i uploaded another pdf with the way i would solve this. and what i understand is , if my solution is right , that my teacher was wrong and i need to ask him that again .
Edit:
hi, i uploaded another...
hello , I am adding pdf with the questions and what i tried to do to solve them.
in the first question my teacher just taught us that if there is a frictionless floor and i push the upper block (m) with force F toward me then if the static friction will be toward me too. so the lower block M is...