Recent content by nko315

Solution. Woo hoo Npsin(θ ) − 30N/m(r − .25m) = .08kg(r'' − rθ'2) F−Npcos(θ ) = .08kg(rθ'' + 2r'θ') If you work this all the way out it finally does work out to 7.67N

Drawing for Hibbler 13-97 I attached a word drawing of the dynamics problem. Hopefully it will make the problem clearer. Thanks

Homework Statement Smooth particle with mass of 80 grams is attached by an elastic cord from O to P. O is at the base of a circle with radius .4m. Angle theta is 60deg from horizontal. The cords unstretched length is .25m. K of the cord is 30N/m The path the particle makes is...