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## Homework Statement

Smooth particle with mass of 80 grams is attached by an elastic cord from O to P. O is at the base of a circle with radius .4m. Angle theta is 60deg from horizontal. The cords unstretched length is .25m. K of the cord is 30N/m

The path the particle makes is r=0.8sin(theta)m. The constant angular velocity is 5 rad/s. An arm moves this particle.

## Homework Equations

What I am looking for is the force that the guide has on the particle. This particular one is in the horizontal plane so gravity is out. How do you do this?

## The Attempt at a Solution

Force that the cord produces is (0.69m-.25m)30N/m or 6.64 newtons

The listed answer is 7.67N. I know this has something to do with the tangential and normal forces due to the particle itself.