Recent content by NotMrX

The statement c isn't technically right and g is unclearly worded to me. For statement C if there are an odd number of electrons it is still diamagnetic. By most standards diamagnetic means no unpaired electrons and if there are an odd number electrons it going to have to be unpaired. A...

you could hang the mass from the spring into a bucket of water

no it will be near 0. X represents Ce3+ concentration and that number minus x represent the Ce4+ Solve x using quadratic. Subtract from that number. Then Ce4+ ends being a pretty small number

The voltage is a constant determined by the battery. The battery lasts the longest when there is the least amount of power getting used. Since P=IV and the voltage drop across the entire circuit is a constant determined by the battery, then the current is the only factor left. Is the current...

And use a fume hood. That is above the azeotropic concentration and has a lot HCl pressure

Yeah I don't think sorbothane can have that much weight so maybe I will use some on the sand if the sand doesn't do the trick by itself

I am sorry for arguing. I don't have any bad feelings. I just wanted to make clear my view points. Thank you for your help I really do appreciate it. Anyways, once I put that ton of sand in it is going to be hard to move and mess with the table. I was thinking if I could find small inner...

I see what you are saying. Sound frequencies are much lower than that. They were saying in the video that the amplitude of the vibration of film should be less than 1/10 of the of the light wavelength. A little different context. Suppose I need a 5 second exposure time. Then the frequency is...

I got that info from this video http://youtube.com/watch?v=XtvAhL1lzOI I will rewatch it later to make sure I didn't misunderstand them

the following link shows a better picture in my opinion http://www.uncp.edu/home/mcclurem/lattice/hcp.htm the first picture shows the just two layers. The third layer should stack right on top of the other layer. The conceptual point is that a pyramid is formed from three spheres on the...

You probably won't want to set h = 4r. I mean that isn't the easiest way. I was just trying to get you to realize that path of radii entered into the crystal unit. The way I solved was by visualizing four spheres making a pyramid. Then find the height of that period as function of the radius of...

It is hard to tell from the picture but side labeled h is not 4r. The third layer is in the same spot except for that is translated vertically. The second layer fits in the valleys of the first layer. The points of contact of the sphere make the radii line not travel along one of the faces but...

No, but I do have an excellent laser. I can buy film, beamsplitter, mirrors, lenses etc from edmington scientific. I was thinking about making my own front side mirrors using tollens reagent or something similar. Maybe not...as soon I am sure how to do it safely.

I have no practical and theoretical knowledge of physics? That's your opinion. http://www.instructables.com/id/EWSD3J2NOBES9J5XZT/ http://home.moravian.edu/users/phys/mejjg01/interests/apparatus_pages/holography_table.htm Seems to have worked for these people. You don't have to...

R)____Ce4+___ +_________ Fe2+___⇌___Ce3+___+_Fe3+ I) .008*.12/.015 ______.007*.3/.015______0_________0 C)_____-x _______________-x ___________x ________x E) .008*.12/.015 -x ____.007*.3/.015 _____x ________x k=\frac{x*x}{(\frac{0.008*0.12}{0.015}-x)(\frac{0.007*0.3}{0.015}-x)}