Recent content by novamatt
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AS Mathematics - Core 1 - Indices Problems
thanks for the assistance its a bit late for me to crack on with the problem at the moment I will return tomorrow and have another go. Could you please tell me how you put the 1/2 index power or direct me to a link where I can learn how to do this... is it simply html code like the ones...- novamatt
- Post #4
- Forum: Precalculus Mathematics Homework Help
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AS Mathematics - Core 1 - Indices Problems
I am struggling with my mathematics indices homework. I think I have some correct answers so far but I'm pretty stumpted on some others. How would I go about solving the following equations. Homework Statement 1) 25 to the \frac{1}{2} - \frac{5 to the -4}{5 to the -5} Homework...- novamatt
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- Core Indices Mathematics
- Replies: 4
- Forum: Precalculus Mathematics Homework Help
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Potential Energy/Work done question AS Level Physics - Mechanics
thanks I see now that you had already explained the force was not a constant and can now see where the equation in my notes 1/2kx² comes into play. =) I shall return to you for pointers in the future you've been a great help- novamatt
- Post #5
- Forum: Introductory Physics Homework Help
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Potential Energy/Work done question AS Level Physics - Mechanics
thank you for those equations they are not in my notes anywhere... and thank you for taking the time to help me with my problem so... F = 1(x10 to the -6)m² x 2(x10 to the 11)Nm / 2m = 100000Nm 100000Nm x 0.0025m = 250 Nm² Work Done = 250Nm² x 0.0025m = 0.625 J still this...- novamatt
- Post #3
- Forum: Introductory Physics Homework Help
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Potential Energy/Work done question AS Level Physics - Mechanics
Homework Statement The question posed - Calculate the work done in a steel wire (Esteel = 200GPa) 2.0m long and 0.010cm² in cross-sectional area extends by 2.5mm when loaded. so Length (L) = 2m Area (A) = 1(x10 to the -6)m Extension (x) = 0.0025m Ep? = 2(x10 to the 11) Nm...- novamatt
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- Mechanics Physics Potential
- Replies: 4
- Forum: Introductory Physics Homework Help