Recent content by npellegrino

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    Find Derivative - Get Guidance Here

    This is what I have so far. I believe i use this rule d/dx log a ^ u = 1/(lna)u so ln = 1 a = ln u = (1+e^sqrtX)/(2-e^cosx) now i need to take the derivative of u, does e^sqrtX = e^sqrtX or is it e^sqrtX * derivative of sqrtX making it e^sqrtX * 1/2sqrtX d/dx u =
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    Find Derivative - Get Guidance Here

    I am having difficulty figuring this one, any guidance will be appreciated.
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    How can I use probability to solve a dice problem with a two-dice table?

    Yes, 2 was tricky, it's the factors of the sum that are only even. But would I consider all 36 sums or only the 12 (2,3,4,5,6,7,8,9,10,11,12) hmmm
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    How can I use probability to solve a dice problem with a two-dice table?

    Draw a table for throwing two dice (one red one blue). Find the probability. 1. That the sum is divisible by seven 2. The sum has factors whose sum is even 3. The sum is a composite number. My solutions: 1. 1/6 2. 7/11 3. 7/12 Work is attached: Any advice would be great. Thanks...
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    Draw a probability table for throwing two dice

    Also i believe the 3rd problem is 21/36
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    Draw a probability table for throwing two dice

    I am questioning my solution for the 2nd problem, wouldn't it be 7/11 since there are only 11 possibile sums (2,3,4,5,6,7,8,9,10,11.12) and the factor's sums are only even for (3,5,6,7,10,11,12)? I attached my work below.
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    Draw a probability table for throwing two dice

    Draw a table for throwing two dice (one red one blue). Find the probability. 1. That the sum is divisible by seven 2. The sum has factors whose sum is even 3. The sum is a composite number. My solutions: 1. 1/6 2. 7/36 3. 31/36 Any advice would be great. Thanks in advanced.
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    What are the critical numbers of the function f(x) = x*sqrt2x+1?

    Find all critical numbers if any. I found the critical number -1/3 , just checking my work. Any input would be great. the function f(x) = x*sqrt2x+1 f'(x) = (3x+1)/sqrt2x+1 3x+1 = 0 , x = -1/3
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    Mean Value Theorem for f(x) = √x - 2x on [0,4]

    Alright i think i solved it... finally thanks for the help i really do appreciate it from you 2 :)f(4) = -6 f(0) = 0 which gives me -6/4 the derivative 1/2sqrtX -2 = -6/4 which will give me 1/2sqrtx = 1/2 then x = 1
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    Mean Value Theorem for f(x) = √x - 2x on [0,4]

    f(4) = sqrt4 - 8 = -6 f(0) = sqrt0 - 2(0) = 0
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    Mean Value Theorem for f(x) = √x - 2x on [0,4]

    Alright I'm having a brainfart i see what you are saying.
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    Mean Value Theorem for f(x) = √x - 2x on [0,4]

    maybe my professor has taught me wrong?
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    Mean Value Theorem for f(x) = √x - 2x on [0,4]

    You are not taking the derivatives of f(b) and f(a)... the mean value theorem states that if f is continuous on the closed intervals [a,b] which in this case is [0,4] and differentiable on the open interval (a,b,) then there exists a number c in (a,b) such that
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    Mean Value Theorem for f(x) = √x - 2x on [0,4]

    the derivative i got for f(x) is 1/2sqrtX - 2 then i set that equals to (f(b)-f(a))/b-a which is 1, so I'm trying to figure 1/2sqrtX - 2 = 1 and I'm having trouble figuring the fraction