Recent content by Nuclear_eng

Thank you very much Lawrence. I was getting my units for Cp messed up but I've now managed to get 15.1°C.

I used the following equation to calculate work done and when I used n=5/3 I got 72kJ. Work done = (P1V1-P2V2)/(n-1) Work done = ((0.1 x 8e5)-(0.8 x 0.4e5))/((5/3)-1) = 72kJ My understanding really isn't great on this. I think I might leave it till I start the course in October and ask...

Thanks chester. That sounds much more promising but I wonder why it's a factor of 10 out. Could I ask how you got 7.2kJ? What were the equations you used?

Is there no one who can help me? I've been looking at this similar question I found on the forums and I can't get 184°C by using the SFEE. I think I must be making a mistake with the units or something really stupid. https://www.physicsforums.com/showthread.php?t=249494 Could somebody...

I come from a civil engineering background and I'm about to start a masters in nuclear energy. I have no experience in thermodynamics and I've been doing a bit of revision before the course commences to get me up to speed. I've been working my way through 15 revision questions and I only have a...

The problem was given to me by a lecturer to do over summer before I start the course. I'm still having no luck with this question. Has anybody actually managed to get 72kJ as their answer?

hmmm I tried using n=1.44 and I got a value of 109kJ. I used the equations on the following link http://www.roymech.co.uk/Related/Thermos/Thermos_Thermodynamics.html Thanks for the help though. I think you've helped me gain more of an understanding although I still haven't quite got the...

When I first attempted the question I came to the same conclusion as you have above but I didn't have enough confidence in my own understanding of the subject to be sure I was right. I think I'll leave this question now and move on to some other topics. Thank you very much for the help, much...

Do you think something is missing from this question? I've really been struggling with it and according to the textbook the change in entropy is 146.5 J/K, not zero. Also have you actually been able to get the correct answer of 72 kJ for the work done? Thanks for the help

I thought in an isentropic process the entropy doesn't change? The second part of this question asks for the change in entropy? I'm confused. Can you not provide me with some more useful information. I've been studying thermodynamics pretty solidly for the past two weeks but I'm really...

I come from a civil engineering background and I'm about to start a masters in nuclear energy. I have no experience in thermodynamics and I've been doing a bit of revision before the course commences to get me up to speed but I'm really stuck on the following problem although it should be pretty...