Recent content by Nykrus

The maximum of sin(x) is 1

Hmmm... okay, let's simplify this: 2/L is just a constant, and so's \frac{n\pi}{L}, so that gives us: \psi^2(x)=A\sin^2\left(ax) Sine functions go to 1 when ax = 90, and since sin2(ax) is : \sin^2\left(ax) = \sin\left(ax)\sin\left(ax) This means... I'm seriously clutching at straws...

Ah, I see - half the maximum value. I'm guessing it'd only be 1 if we were considering the entire box, not one point. Alright, so you determine the maxima by differentiation? \frac{d\psi^2(x)}{dx}=2\sin\left(\frac{n\pi x}{L}\right)\cos\left(\frac{n\pi x}{L}\right)=0

Homework Statement An electron is confined to the region of the x-axis between x = 0 and x = L (where L = 1nm). Given a state n = 3, find the location of the points in the box at which the probability of finding the electron is half it's maximum value Homework Equations...