Using h = vt - 1/2at^2, I've gotten the quadratic (-4.9t^2 + 9.249t + 3). From there, to determine the velocity (magnitude), I isolated the portion of the parabola between y = 3 (x = 1.888) and y = 0 (x = 2.17). I'm just unsure of how to find the time with the diver starting 3 meters above the...