Uneven start/end points (2D Kinematics) (1 Viewer)

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1. The problem statement, all variables and given/known data
A diver springs upward from a board that is 3 meters above the water. At the instant she contacts the water her speed is 9.30 m/s and her body makes an angle of 84.0º with respect to the horizontal surface of the water. Determine her initial velocity, both magnitude and direction.

2. Relevant equations
h = v(i) * t - 1/2at^2
t(half) = (v * sin(x))/g
d = (v^2 * 2sin(x) * cos(x))/g

3. The attempt at a solution
Tried using h = v(i) * t - 1/2at^2 to find the initial velocity (with h as 3).
Unsure exactly of where I should be headed...

*SOLVED*
 
Last edited:
Using h = vt - 1/2at^2, I've gotten the quadratic (-4.9t^2 + 9.249t + 3). From there, to determine the velocity (magnitude), I isolated the portion of the parabola between y = 3 (x = 1.888) and y = 0 (x = 2.17). I'm just unsure of how to find the time with the diver starting 3 meters above the water.
 

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