Recent content by objective33

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    Repulsion between two small spheres

    Through my reasoning, I found the answer. Charge of one electron = 1.602 x 10^-19 C Charge of a sphere = 1.602 x 10^-19 x 1.0 x 10^8 C F = (1/4piÈ) Q1Q2/d^2 (1/4piÈ) is a constant equal to 9 x 10^9 F = 9x10^9 x (1.602x10^-11) x (1.602x10^-11) / 1 F = 2.3 x 10^-12 N
  2. O

    Repulsion between two small spheres

    Homework Statement Calculate the force of electric repulsion between two small spheres placed 1.0 m apart if each has a deficit of 1.0 x 10^8 electrons. Homework Equations N = q/e qe = mg q = mg / e q = mgr / Vb e = 1.602 x 10^-19 C. k = 9 x 10^9 - not sure if relevant or not. Fe = qe...
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