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Repulsion between two small spheres

  1. May 7, 2009 #1
    1. The problem statement, all variables and given/known data
    Calculate the force of electric repulsion between two small spheres placed 1.0 m apart if each has a deficit of 1.0 x 10^8 electrons.


    2. Relevant equations

    N = q/e
    qe = mg
    q = mg / e
    q = mgr / Vb
    e = 1.602 x 10^-19 C.
    k = 9 x 10^9 - not sure if relevant or not.
    Fe = qe
    Answer ( as stated in the textbook): 2.3 x 10^-12N
    3. The attempt at a solution
    Fe = qe?
    r = 1. 0 m
    e constant used
    g = 9.8 N/kg?
    Fe = (1.0 x 10^8 C)( 1.6 x 10^-19 C)x (1.0m/9.8N/kg) = 1.63 x 10^-12 N.
     
    Last edited: May 7, 2009
  2. jcsd
  3. May 8, 2009 #2
    Through my reasoning, I found the answer.


    Charge of one electron = 1.602 x 10^-19 C
    Charge of a sphere = 1.602 x 10^-19 x 1.0 x 10^8 C

    F = (1/4piÈ) Q1Q2/d^2
    (1/4piÈ) is a constant equal to 9 x 10^9
    F = 9x10^9 x (1.602x10^-11) x (1.602x10^-11) / 1
    F = 2.3 x 10^-12 N
     
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