It's a lot clearer if you re-write your equations in a slightly different form:
v = v_0 + a t
s = v_0 t + \frac{1}{2} a t^2
v^2 = v_0^2 + 2 a s
Where s is the displacement [itex]x-x_o[/tex] (hint hint).
I've thought carefully about this because I don't want to send you down the wrong path, and I'm pretty sure that as they ask only for translational energy, you only need worry about the downward movement of the centre of mass of the lower cylinder in a straight line.
Ok, I might be wrong, but seeing as the question asks only for translational velocity, and the radii of the cylinders are not given, I would go as far as to say that the part of kinetic energy that deals with rotation of the body is unnecessary.
I think you can simply put:
mgh =...
Your friend is right about conservation of energy. You should think about the relationship between the translational kinetic energy of the cylinder and its gravitational potential energy. Once you've figured that out, try comparing the situation before and after the cylinder is released.
Well your equation seems correct and with the values as given so does your answer... My concern is with the description of the area in the question as stated. Is it possible that the questioner intended to write that as an area of 2^2 cm^2 = 4 cm^2? That would account for the factor of two.
You've clearly never lost your keys. :p But seriously, you're on the money. A good explanation of the double-slit experiment, which really helped my comprehension of this phenomenon can by found in Feynman's book Six Easy Pieces. He also had http://www.youtube.com/watch?v=wMFPe-DwULM" to say...
Ken G is right. However, you can think of an oscillator as tracing out the shape of a wave as it oscillates. Analogous to this is the situation of electrical charges which may oscillate, causing the medium they make up to emit an electromagnetic wave.
First of all the equation you've used here is for a traveling wave (as you say, it's a wave moving in the positive x direction) so it's not going to be very helpful for dealing with a standing wave.
Try adding together two waves of the same frequency and amplitude but going in opposite...
Well what I think you should do is think about Newton's second law, which is frequently formulated as:
f_{net}=ma
That is to say, the net force exerted on an object is proportional to its acceleration. Think about the net force acting on the brick, and then break that force down into its...
Hello all, I'm doing a question for the maths module in my physics degree (I'm a second year undergrad) and there's a question I'm doing on basis functions.
Homework Statement
Verify that functions of the type f_{n}(x) = A cos \frac{2\pi n x}{L} where n = 0,1,2... can be used as a basis...
I don't know much about Captain America, but with regards to your second question I would have thought it would be preferable for the shield to have as low a rebound speed as possible after hitting its intended target. This way, its kinetic energy must have been dissipated into said target...