Basic integration identity- please jog my memory

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Homework Help Overview

The discussion revolves around verifying that functions of the type f_{n}(x) = A cos \frac{2\pi n x}{L} can serve as basis functions within the interval 0

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to integrate the product of two cosine functions with different arguments to check orthogonality but encounters difficulties with integration by parts, leading to a repetitive cycle. They inquire about potential identities that could simplify this process.

Discussion Status

Participants have provided guidance by suggesting the use of trigonometric identities to facilitate the integration process. The discussion is ongoing, with multiple approaches being explored without a clear consensus on the best method yet.

Contextual Notes

The original poster has already normalized the function and is seeking assistance specifically with the orthogonality check. There is an implied need to adhere to homework guidelines, which may limit the type of assistance that can be provided.

Oscur
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Hello all, I'm doing a question for the maths module in my physics degree (I'm a second year undergrad) and there's a question I'm doing on basis functions.

Homework Statement



Verify that functions of the type [tex]f_{n}(x) = A cos \frac{2\pi n x}{L}[/tex] where n = 0,1,2... can be used as a basis function for 0<x<L.

There are then three parts:

i. Normalise (I've done this part, I found a normalising factor of [tex]A=\sqrt{\frac{2}{L}}[/tex]

ii. Check orthogonality (this is the part causing the trouble)

iii. Would it be possible to use [tex]f_{n}(x)[/tex] as the basis for all functions in this interval? (this clearly follows from the other two parts, so once I've done ii, I should be able to answer this)

Homework Equations



To check orthogonality, I need to demonstrate that the condition:

[tex]\int f_{n}(x) f_{m}(x)dx=\delta_{n,m}[/tex], where the limits of the integral are the same as the interval of interest, is met.


The Attempt at a Solution



This means I need to integrate the product of two cosines with different arguments, and if I try and do this with integration by parts, I end up in an infinite loop with products of cyclic functions. Is there an identity for this?

Thanks in advance!

Matt
 
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Hello Matt! :smile:
Oscur said:
This means I need to integrate the product of two cosines with different arguments … Is there an identity for this?

It's one of the standard trigonometric identities …

cosAcosB = 1/2 [cos(A+B) + cos(A-B)] :wink:
 
Much appreciated, thank you!
 
Try using a trig identity to write cos(nx)cos(mx) in terms of cos((n-m)x) and cos((n+m)x).
 

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