Recent content by osob

I believe I can now do these questions on my own. Through all the errors and trials, I appreciate your help so much Chestermiller.

OR tan theta = 2.87 / 7.36 = 21 degrees

ok i created a right angle triangle... tan(theta) = opp /adj hypotenuse is 7.89 rx = 7.36 ry = 2.87 tan theta = 7.89 / 7.36 = 46.99 degrees Does this look right? :nb)

Yes now I do. Phew I went a long way from my original thread, I appreciate the help Chestermiller. So for part c, R = rx^2 + ry^2 = (7.36)^2 + (2.87)^2 =7.89 As for part d, I would have to use the sine law? I am totally stuck here. R = 7.89 angle = 23 degrees B = 8.0 angle = ? angle R...

magnitude of R on the x axis: ax = 6cos90 = 0 bx = 8cos23 = 7.36 rx = ax + bx rx = 7.36 along the y axis: ay = 6sin90 = 6 by = -8sin23 = - 3.13 ry = ay + by ry = 2.87 B is pointing down, meaning its negative... but I still don't know what I'm supposed to do with that information .. Am i...

Hmm I'm not quite sure how to do that... Do I have to solve for the x and y-axis separately? for x-axis do i have to do this: 8cos23 = 6cos23 = and y axis: 8sin23 = 6sin23 = And I'm also confusing myself because am I supposed to use 23 degrees or 67degrees? and why?

Hi everyone, I need steps and some guidance on how to solve questions like this. I know how to do right triangle questions using the Pythagorean method, but when it comes to these non right angle triangles I get so confused. Help! 1. Homework Statement Homework Equations a) The magnitude...