Recent content by palkia

In the last case,when we connect the voltmeters ,my book states that I3=I1+I2 but I am not sure How it came

V1=E- I1R1 V2=E-I2R2 V3=E-I3R3 It's getting bigger to solve as I tried

okay so it makes sense that it shows different readings now...but still How can I proceed if they have different resistance

ideal voltmeter-Which doesn't influence the circuit Real voltmeter-Which has resistance that is not infinitely largeSame for battery

Homework Statement We have to measure emf of a battery. We have to voltmeters. Each of them when connected alone across the battery, they read V1 = 0.9V and V2 = 0.6V and when both of them are connected to the battery simultaneously, they both read V3 = 0.45V . What is the emf of...

Why don't wires in any circuit touch each other and get short circuited? If two current carrying wires carry charges in same direction then from ampere's law,can't they touch each other due to attractive forces?

Got that

I have read it sir...I understood that part about the maximum stress

The tension will be - (mg/L)*x where x is the distance from the bottom Elongation...it should be the force causing the elongation ...in this case the weight so it is (W/AY)dx where dx is the length of the segment

I think the book considers the bar and wire to be same because they have done the integration using the weight per unit length

Yep.It's the weight of the bar...I kinda mixed the wire from the first case In the second case,some stress will be acting because the width gets elongated...I have heard that young's modulus makes sense when stress and strain are proportional. In the second case,the wire is acting along the...

In the second case,the wire gets elongated but the restoring force that is tension remains constant but it;'s width get elongated so will stress also act in that case?

Makes sense then.So the uppermost point is most probable to break first So the strain will not tell us the condition for breaking but the stress will,right? If the breaking stress is equal to the external force (weight) at the topmost point then beyond this the wire breaks,right?What does...

Since at the top,the maximum tension acting on is the weight of the wire mg (Why are we calculating this for the upprmost point tho)If at breaking stress,it has to elongate before it breaks then can we use the formulae of strain here maybe

Since the stress is magnitude of the internal restoring force per unit which in this case is the tension then it will be greatest at the top How exactly did you know to apply the formulae for strain in the second case...I struggled a lot for that My definitions prior to solving a question for...