Recent content by PassThePi
-
P
Total Power Radiated by Isotropic Source: 1.885mV
Oh I think I see... Prad(theta,phi,r) = (1/2)*eta*|E|^2 Prad(theta,phi,r) = (1/2)*377*0.001^2*(10000) = 1.885mV PradTotal = (int(0|2*pi))(int(0|pi))(Prad(theta,phi,r)*r2sin(theta)dtheta*dphi PradTotal = 2*pi*0.132*(-cos(\0|pi)) = 0.528*pi- PassThePi
- Post #3
- Forum: Introductory Physics Homework Help
-
P
Total Power Radiated by Isotropic Source: 1.885mV
What is the total power radiated by an isotropic source in free space is |E| = 1mV/m at a distance of 10km? Relevant Eqns: Prad(theta,phi,r) = (1/2)*eta*|E|^2 Prad(theta,phi,r) = (1/2)*377*0.001^2*(10000) = 1.885mV Is this correct? I feel like it can't be that simple.- PassThePi
- Thread
- Power
- Replies: 2
- Forum: Introductory Physics Homework Help
-
P
What is the relationship between A and B in the given equation?
Homework Statement E = [axhat(A(x+y)) = ayhat(B(x-y))]cos(wt) Determine the relationship between A and B Homework Equations I don't know if there are any.The Attempt at a Solution I've expanded the problem and reduced it to E = cos(wt)[x(A+B)axhat + y(A-B)ayhat] I was going to take the real...- PassThePi
- Thread
- Relationship
- Replies: 1
- Forum: Calculus and Beyond Homework Help
-
P
Charge enclosed in cylinder question
Homework Statement The electric field inside a circular cylinder of radius r = a and height z = h is given by: E = Az[(-c/h)+(b/6(epislon zero)*(3z^2 - h^2) where c and b are constants. Assuming the medium within the cylinder is free-space, find the total charge enclosed within the...- PassThePi
- Thread
- Charge Cylinder
- Replies: 1
- Forum: Engineering and Comp Sci Homework Help