Total Power Radiated by Isotropic Source: 1.885mV

  • Thread starter Thread starter PassThePi
  • Start date Start date
  • Tags Tags
    Power
Click For Summary
SUMMARY

The total power radiated by an isotropic source in free space with an electric field strength of |E| = 1mV/m at a distance of 10km is calculated using the formula Prad(theta,phi,r) = (1/2)*eta*|E|^2. Substituting the values, Prad(θ,φ,r) results in 1.885mV. However, to determine the total power radiated, integration over the entire surface area of the sphere at that radius is necessary, leading to a more complex calculation involving PradTotal = (int(0|2*pi))(int(0|pi))(Prad(theta,phi,r)*r^2sin(theta)dtheta*dphi).

PREREQUISITES
  • Understanding of electromagnetic wave propagation
  • Familiarity with isotropic radiation concepts
  • Knowledge of integration techniques in spherical coordinates
  • Proficiency in using the formula Prad(theta,phi,r) = (1/2)*eta*|E|^2
NEXT STEPS
  • Study the derivation of the isotropic radiation formula
  • Learn about the implications of electric field strength in free space
  • Explore integration in spherical coordinates for electromagnetic applications
  • Investigate the significance of the impedance of free space (η = 377 ohms)
USEFUL FOR

Students and professionals in electrical engineering, physicists studying electromagnetic theory, and anyone involved in antenna design and radiation pattern analysis.

PassThePi
Messages
4
Reaction score
0
What is the total power radiated by an isotropic source in free space is |E| = 1mV/m at a distance of 10km?

Relevant Eqns:
Prad(theta,phi,r) = (1/2)*eta*|E|^2

Prad(theta,phi,r) = (1/2)*377*0.001^2*(10000) = 1.885mV

Is this correct? I feel like it can't be that simple.
 
Last edited:
Physics news on Phys.org
Your 1mV/m is measured at a point 10Km away, to calculate the total power of the isotropic source( E is equal in magnitude at any point on the sphere), you need to have some sort of integration of the whole surface of radius of 10Km.

I don't understand your formula at all!
 
Last edited:
Oh I think I see...

Prad(theta,phi,r) = (1/2)*eta*|E|^2

Prad(theta,phi,r) = (1/2)*377*0.001^2*(10000) = 1.885mV

PradTotal = (int(0|2*pi))(int(0|pi))(Prad(theta,phi,r)*r2sin(theta)dtheta*dphi

PradTotal = 2*pi*0.132*(-cos(\0|pi)) = 0.528*pi
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
6
Views
3K
Replies
2
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
17
Views
2K
Replies
4
Views
2K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K