Oh I figure out my mistake, I wasn't doing 0.03kg * 2090 because I thought since the change in T was zero it wasn't significant. I guess the student really is going to spend the time adding 621 ice cubes o_0
Thanks for all the help! :)
Oh, it continues to heat up?
So I need to add 0.03kg(4186)(16-0) to the demoninator? But it still comes out to the wrong answer. I get 625 ice cubes.
I did 7534800 / (10050 + 2009.28) <--- Original demoniator plus the energy from continued heating.
Okay, so I've approached this problem from a number of different ways and have gotten some crazy answers. The poor student would be spending the day in a bath of ice if my answers were right :P
Here's the problem :
Trying to beat the heat of the last summer, a physics student went to the...
Okay, so I'm stuck on the last part of the problem :
A hydraulic lift has two connected pistons with cross-sectional areas 15 cm2 and 430 cm2. It is filled with oil of density 620 kg/m3.
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a) What mass must...
Oh okay! I have no idea why I subtracted 124kg instead of adding it, but that was the problem. Thanks!
The mass turned out to be 672.88kg for the car :)
Okay, well I set the two equations equal to a common variable to solve for it, but I end up with both constants (k) cancling each other out. And if I solve for k the mass just comes out to 124kg which isn't right :-\
My work :
http://img368.imageshack.us/img368/4701/workxi1.jpg
Okay, well I tried to approach the problem from another direction, but I'm still not getting the correct mass of the car :(
I tried to solve k in a different manner and then use that to solve for Mcar in the equation I was going to use initially. I'm really confused now lol
My Work ...
Another question from me yet again!
Two geekie physics students with a combined mass of 124 kg jump into their old car to run out for some late night pizza. The distance between the front and back axles of the car is 2.8 m. When they get in the car, the springs compress a total of 8.7 cm. On...
Oh I see, I kept reading the x coordinate as cm for some reason! Thanks a lot, I totally overlooked that.
I got the right answers too :)
Vmax = 0.0157m/s
A = 4.81 * 10^-4 J
http://img179.imageshack.us/img179/2245/springgraph226fe577uv1.jpg
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A 3.9 kg block is attached to a horizontal spring and undergoes simple harmonic motion on a frictionless surface according to the graph shown...
Ahhh, so I solved torque, but that's isn't to force, it's the product of the force and radius.
Thanks for the help :)
I knew something had to be wrong with my answer since I was pretty sure torque =/= the frictional force.
Okay, another problem from me!
http://img187.imageshack.us/img187/69/32aa2d25kf9.jpg
A solid sphere of uniform density starts from rest and rolls without slipping a distance of d = 2.6 m down a q = 22° incline. The sphere has a mass M = 4.2 kg and a radius R = 0.28 m...
Alright thanks guys! I misread the problem and was thinking that the friction was occurring on the pulley and not the block on the table. Which would also make sense as why I was confused that it said the rope didn't slip and thought it said there was friction! lol
The additional part I...