Recent content by PBTR3

Yes! I am very much a novice at this and when books give an answer it usually helps greatly BUT when the answer published is wrong it causes much difficulty. Yes that is my typo. I am not perfect either. Also I throw out the odd powers because the integral they represent is zero from...

I am still trying to figure out how to fix that relevant equation post.

(a + a*)^4= a^4+a^3a*+a^2a*a+a^2a*2+aa*a^2+aa*aa*+aa*^2a+aa*^3+a*a^3+a*a^2a*+ a*aa*a+a*aa^2+a*^2a^2+a*^2a^2+a*^2aa*+a*^3a+a*^4 then throw out all terms with unequal powers of a and a* which are 0. ##\langle n | a^2a*^2 | m \rangle=\langle n | (m+1) (m+2) | m \rangle## Results for the rest are...

The book(Schaum) says the above is the solution but after two hours of tedious checking and rechecking I get 2n^2 in place or the 3n^2. Am I missing something or is this just a typo?

I could not get the Latex Preview to work until now. This is more like what I intended.

##\frac {\delta I[f]} {\delta f(x_o)} = \int_a ^b \delta(x-x_o) \, dx## with a=-1 and b=+1 ## -1 \leq x_o \leq +1 ## vs ## -1 \lt x_o \lt +1 ##, 0 otherwise. Which is correct and does it matter when doing integration by parts?

I Great. Now I will spend some time (maybe weeks)going through your math (at 4AM?) in detail. This also implies that if m approaches zero and light is c that E=pc for a free, massless, relativistic particle, which is what I am trying to prove.

Thanks. The photon should have an energy operator(Hamiltonian?) I need to learn how to use LaTex. It does not seem to work with Android or Linux. When I get that worked out I will resume this thread.

I agee but I should be able to show E=pc for a photon. I can use Lagrange's diff equation to recover F=ma for a nonrelativistic free particle. I can use Schoedinger's diff equation to recover E=1/2mv^2 for a nonrelativistic free particle. There should be a diff equation that recovers E=pc...

c

Yes

It is easy to derive E=1/2mv^2 from the Schroedinger equation for the nonrelativistic one dimensional case where e^ipx-iEt/\hbar is the free traveling wave function: i\hbar x -iE/\hbar x e^ipx-iEt/\hbar = - - \hbar^2/2m x p^2/2m x e^ipx-iEt/\hbar which reduces to E=1/2mv^2 Where should I start...

Symmetry is an important way to find new physical laws according to Feynman. The equation that describes the electric field and the gravitational field are quite similar. Since the electric and magnetic fields are well defined by the Maxwell equations could it be possible, by symmetry, that...

Energy of photon vs classical physics energy Thanks for the replys. I was trying to understand what happens to energy of a proton as a proton is accelerated from rest to almost the speed of light as in the LHA. I think I can calculate that now. hjr