Recent content by pedro_bb7

Thanks, very nice the wolfram site. Nice idea you got to solve it.

Thanks, that is the right way. Could you check the answer for me? \frac{\pi}{5}

[PLAIN]http://img716.imageshack.us/img716/3663/semttulont.png f(x) = 0 (|x| > 1) = x² (|x| < 1) I know that thing on integral is [F(x)]^2, but I have no clue what to do now.

Thanks, finally I got the right answer. You helped me a lot.

I got this: Bn = (2*(-1)^n)/(2-n)^2 - (2*(-2)^n)/(2+n)^2 B2 = (2/(2-2)^2) - 1/8 What did you make to get that: \frac {\pi^2} 3

Thanks, the problem was at the B2. Cya.

Its hard to explain. I did this exercise a lot of times, every time I get the same answer. I can post the whole exercise to help me find what is wrong. That Bn is kind hard to get right.

[PLAIN]http://img826.imageshack.us/img826/6708/semttulocz.png

Can you help me, please?

Hello, I got a problem using Fourier series. f(x) = sin(2x)*(x^2) (-pi < x < pi) I got this answer, although it seems to be wrong. f(x) = (-16/9)*sin(x) + (-1/8)*sin(2x) + sum((2*(-1)^n/(2-n)^2 - 2*(-1)^n/(2+n)^2)*sin(nx) , n, 3, 100)