Solving Fourier Transform Problems with Wolfram Alpha

Click For Summary

Homework Help Overview

The discussion revolves around applying Fourier Transform techniques to a specific function defined piecewise, where f(x) is zero outside the interval [-1, 1] and equals x² within that interval. Participants are exploring methods to evaluate the integral related to the Fourier Transform of this function.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants suggest applying Parseval's theorem as a potential method for solving the problem. There are inquiries about the correctness of the results obtained through Wolfram Alpha, indicating a focus on verifying calculations.

Discussion Status

The conversation includes attempts to validate the output from Wolfram Alpha, with some participants expressing confidence in the approach suggested. However, there is no explicit consensus on the final answer, and the discussion remains open to further verification and exploration.

Contextual Notes

Participants are working within the constraints of homework rules, which may limit the extent of guidance provided. The original poster expresses uncertainty about the next steps after identifying the integral related to the Fourier Transform.

pedro_bb7
Messages
11
Reaction score
0
[PLAIN]http://img716.imageshack.us/img716/3663/semttulont.png

f(x) = 0 (|x| > 1)
= x² (|x| < 1)
I know that thing on integral is [F(x)]^2, but I have no clue what to do now.
 
Last edited by a moderator:
Physics news on Phys.org
Try applying Parseval's theorem.
 
vela said:
Try applying Parseval's theorem.

Thanks, that is the right way.
Could you check the answer for me? [tex]\frac{\pi}{5}[/tex]
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K