Recent content by pegasus24

I have already tried that but the answer is too small.. It should be 1. something but when i use this 20 degree angle i get 0.07 something... which is totally wrong..

I tried with 4m but it is still wrong..

\tau = (1700kg)(9.8m/s2)(5m) + (1000kg)(9.8m/s2)(7m) = 151900kgm2/s2 I = Ib + Ig = \frac{1}{3}(1700kg)(8m)2 + (1000kg)(7)2 = 85266.67kgm2 \alpha = \frac{\tau}{I} = 1.78rad/s2 But this \alpha is wrong.. where did i go wrong?

When i calculate torque, should I take into account the tension in the cable?

Yes I went through this link. So the Ib = (m/3)L2 Is this right? Then what about inertia for the person and his horse? How to calculate that? The only way I know is I = (1000g)(L-1)2.

Moment of Inertia of bridge: Ib = mr^2 but how to calculate moment of inertia for lost-a-lot?

I took the weight as 41/2 but the calculation is still wrong..

Homework Statement Sir Lost-a-Lot dons his armor and sets out from the castle on his trusty steed in his quest to improve communication between damsels and dragons. Unfortunately his squire lowered the draw bridge too far and finally stopped it 20.0° below the horizontal. Lost-a-Lot and his...

Homework Statement A flexible chain weighing 41.0 N hangs between two hooks located at the same height. At each hook, the tangent to the chain makes an angle θ = 41.5° with the horizontal. (a) Find the magnitude of the force each hook exerts on the chain. (b) Find the tension in the chain at...

Its ok, I figured it out.. Thank you for your hint.. :) \SigmaFx = 0 \SigmaFy = 0 Using these equations I got reaction force as 908.75 N.

Ok I have calculated 1st part: M=145*0.3 Fcos\vartheta=M/0.05 => F=0.96 kN 64.9 degrees above horizontal. What about the second part?

Homework Statement The figure below shows a claw hammer as it is being used to pull a nail out of a horizontal board where θ = 25.1°. A force of 145 N is exerted horizontally as shown. (Assume that the force the hammer exerts on the nail is parallel to the nail.) (a) Find the force exerted...

Thanks a lot.. I got it right now.. T_AC = T_AB cos 35

Homework Statement A bridge truss extends x = 214 m across a river (Fig. P12.68) where θ = 35°. The structure is free to slide horizontally to permit thermal expansion. The structural components are connected by pin joints, and the masses of the bars are small compared with the mass of a 1270...