How do you calculate the forces involved when a claw hammer pulls out a nail?

[pegasus24]

Homework Statement

The figure below shows a claw hammer as it is being used to pull a nail out of a horizontal board where θ = 25.1°. A force of 145 N is exerted horizontally as shown. (Assume that the force the hammer exerts on the nail is parallel to the nail.)

(a) Find the force exerted by the hammer claws on the nail.
(b) Find the force exerted by the surface on the point of contact with the hammer head.

Homework Equations

Moment M=Fd

The Attempt at a Solution

The moment at point of contact would be M = 145N * 30cm
I don't know how to proceed from here.. Any help would be appreciated.

 

[Stephen Tashi]

Find the distance from the point of contact to where the hammer grasps the head of the nail. The nail acting on that lever exerts a counterclockwise torque.

 

[pegasus24]

Find the distance from the point of contact to where the hammer grasps the head of the nail. The nail acting on that lever exerts a counterclockwise torque.

Ok I have calculated 1st part:
M=145*0.3
Fcos$$\vartheta$$=M/0.05
=> F=0.96 kN 64.9 degrees above horizontal.

What about the second part?

 

[pegasus24]

Its ok, I figured it out.. Thank you for your hint.. :)

$$\Sigma$$Fx = 0
$$\Sigma$$Fy = 0
Using these equations I got reaction force as 908.75 N.