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That's irrelevant, because the KE is computed in the laboratory frame (not in the disk frame), where the spatial geometry is Euclidean.

Compute the integral in the interval ##[R-\epsilon R,R]## for small ##\epsilon##, it should explain what's going on.

I think the cause is that the mass distribution is specified in the inertial frame. Then, in the local frame of a rotating piece, as the...

Consider a disc of radius ##R## with a uniform mass distribution and total mass ##M## rotating in its own plane. In its COM's inertial...

Bertozzi even filmed a simple test of this, and somebody put it on YouTube:

As Peter has pointed out, in this thread all you can do is apply the theory. You can call this "doing a thought experiment" if you like...

Just as soon as I finish my post-doc in endocannabinoid pharmacodynamics.

You might like to read this: https://math.ucr.edu/home/baez/physics/Relativity/SR/rigid_disk.html

Then you'll have to do a degree in experimental physics!

Please report back with your test results!

The idea of a disk confuses the issue that within the disk you have particles being accelerated towards ##c##. Each of those particles...

That's a physical inevitability. Nevertheless, the kinetic energy of a spinning disk tends to infinity as the speed of rotation tends to...

Here is a demonstration:

I once asked AI whether some topological thing was true. It gave me a proof I didn't understand. Later mathematicians told me it was...

Why not simply accelerate a particle at constant acceleration until it surpasses ##c##? That's what you are doing to a particle on the...