PeroK's latest activity

Humans deliberately deceive because it is one aspect of intelligence. You say it can't be the case. Why not? That's just another a...

If we go back to the original question, this proves the point to some extent. Or, at least, is strong evidence that an LLM is complex...

:welcome: How many times have you climbed Gran Paradiso?

The lack of agency is an interesting argument. In some ways, it's a Catch 22 since people are so afraid of letting them run loose in an...

When the intensity of the laser beam is very strong, i.e., when the average number of photons is large, then the laser beam can very...

That paper is a far cry from "LLM's always give the wrong answer"!

A paper just published in Nature says that AGI is here, but we don't want to admit it...

Do you mean this in the trivial sense that she cannot see her own reflection, or are you saying that if the test could be modified to...

Indeed. She would have failed the rouge test.

Fortunately, it also works for cards😉

PS note that we can simply add the expected value for each colour: $$E = E(N, R) + E(N, B) + E(N, G)$$

Inspired by the posts by @Gavran we can show that for ##R## red balls and ##N## balls in total, the expected number of red balls at the...

## P(X=g) ## - probability that we have g green cards remaining ## P(X=b) ## - probability that we have b blue cards remaining ## P(X=r)...

I also calculated it to be 1.515 using a different but related method. What the OP is asking for is modeled by the negative...

That would be the same as drawing N cards without replacement that match the first color.