Recent content by Peter Velkov

Equal amounts of charge will flow through the upper or downer R1, and since the resistance is equal the voltage will be too. However I don't understand why the points O and M or N will have the same potential as the resistance along the path is different.

On the upper side we will have a resistor with √2R2, but on the down side R2/√2. So they will be different.

It's symmetrical along MO, NO but that doesn't help us much.

In terms of what? I know i can solve the parallel ones below, however that won't solve it. There should be a way to proof that M and N are also equal to O.

Given an electric circuit, with resistors R1 and R2, find the equivalent resistance R. Data: R1 = √2.R2 Points M and N have the same electric potential so they can be connected with a conductor and this way we get the second circuit.

Yes, it's three dimensional, for a three dimensional point. But can't I integrate it for the whole radius, and then use the standard volume formula? Furthermore, I know Bohr's radius is the mean of the orbit, but can it be used to derive the radius of the atom.

Sorry about the format. I don't know if the last line makes sense. In the way I understand it the negative charge in a point should be p = Ce^(-2r/R). However I think i am wrong. Thank you in advance.

Suppose the hydrogen atom consists of a positive point charge (+e), located in the center of the atom, which is surrounded by a negative charge (-e), distributed in the space around it. The space distribution of the negative charge changes according to the law p=Ce^(−2r/R), where C is a...