Recent content by physical?eer

If anyone has a formula to determine the force created when applied at a distance I'd appreciate it. I'm surprised this is turning into such a complicated question.

I'm not looking for exact numbers so what if we overly simplified this problem as follows (see image). Does that help?

The block of wood is in the middle of the shelf. The shelf is 3 feet wide and 2 feet deep, it is supported in the middle of the shelf. I'm going from the block of wood into the studs with two screws at a 90* angle. From what I understand each screw is capable of supporting >500lbs. I have about...

Black = Wall The red block of wood is 3 inches deep The blue shelf is 2 feet deep If the block of wood is capable of supporting 500 lbs, how much weight can the shelf support if the force is applied downward at the edge of the shelf?

Hello, I am trying to support a shelf with a block of wood. The block of wood is only 3 inches deep and the shelf 2 feet deep. If the block of wood is capable of supporting 500 lbs, how much weight can the shelf support if the force is applied downward at the edge of the shelf? This is a real...

o i just saw your reply! awesome thank you soooo much!

was i wrong?

sounds good...is it?

i got 19.6468827 as velocity

so therefore Ek2 = et1-eg Et1 = 136.73 (1/2 * .565kg * 22m/s^2) so ek2 =109.045 (136.73-27.685) and so there fore...

sorry i don't understand... how does Ek1 = Ek + Eg and even then i don't no Ek:confused:

k i calculate Eg to be 27.685 then i looked at kinetic energy...but that leaves 2 variables velocity and kinetic energy in the formula Ek = 1/2 mv^2 hmm...

wait hold on i think i missed it so at 5.0 m above ground its 22m/s right

ET1 = 0 Et2 = 136.73 (1/2 * .565kg * 22m/s^2) then...

and no gravitational energy