Recent content by physics123

So that would mean the smaller section of pipe would be the 'surviving' one in these questions?

Not sure I catch what you mean by 'survives'. The way I see this, you now how two different pipes of different lengths and I'm unsure which to focus on.

The fundamental wavelength of which part of the tube? The hole effectively breaks the pipe into two different pieces does it not?

Homework Statement A long tube that is open at both ends is used to construct a musical instrument. The sound waves that enter the tube are generated by a taut wire with a tension of 600 N and a linear mass density of 0.031 kg/m. If the length of the tube is 2.4 m and a hole is cut in the side...

Using your equation, 0.302J = (1/2)*30*x2 , x = 0.142 m from rest position. I know that the amplitude is actually 0.266m. What am I missing?

0 + 0.12kg x 4.2 m/s = 0.420 kg x velocity. solve for velocity to get 1.2m/s initially. Now, this is where I get lost. KE = 1/2mv^2 so filling that in I get KE = (1/2)(0.42kg)(1.2m/s)^2 = 0.302J. Which spring energy formula are you referring to? The only one that comes to mind is F=kx and that...

Homework Statement A mass of 120 g rolls down a frictionless hill, reaching a speed of 4.2 m/s. This mass collides with another mass of 300 g that is at rest and attached to a spring with constant 30 N/m. The two masses stick together and enter into periodic motion. What is the equation for the...

i found the answer, thanks everyone

Isobaric: W = P∆V = (2x10^5)(2.23-1.5) = 146000J Q = (C/R)(Vf-Vi)p = 3.5(2.23-1.5)2x10^5 = 511000J Adiabatic: W = (K (Vf1-gamma - Vi1-gamma) )/(1-gamma) where K = PV1-gamma = (2x10^5)2.231.4 = 614690 W = 614690 ( 0.4884-0.72556) / -0.4 = 364524J Q = 0 Isothermic: W = PiVi...

I did the calculations for the W and Q for each PV leg and got: W= 146000 for isobaric, W = 346524 for adiabatic, and W = -415888 for isothermic. Q = 511000 Q= 0 Q = W = -415888 Adding these up I get 94636/95112 = 0.99. I know the...

There is usually a formula for W, but what is the formula for Q?

Homework Statement An ideal gas with Cv = 5 2R, and γ = 1.4 starts at a volume of 1.5m3 , a pressure of 2.0×105Pa ,and a temperature of 300K. It undergoes an isobaric expansion until the volume is V , then undergoes an adiabatic expansion until the volume is 6.0m3 , and finally undergoes an...

Don't you think I would've done that before posting in a forum? Thanks for your help.

I am completely lost beyond that point.

adiabatic processes have no heat transfer (∆Q)