Recent content by pk415

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    Graduate First order pde cauchy problem by method of characteristics

    Ok, so I can get through most of this but I can't seem to get the last part... Here is the problem xU_x + (y^2+1)U_y = U-1; U(x,x) = e^x Characteristic equations are: \frac{dx}{x} = \frac{dy}{y^2+1} = \frac{dU}{U-1} Solving the first and third gives: \frac{U-1}{x} = c_1 The...
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    First Order PDE Cauchy problem Using Method of Characteristics

    Homework Statement Ok, so I can get through most of this but I can't seem to get the last part... Here is the problem xU_x + (y^2+1)U_y = U-1; U(x,x) = e^x Homework Equations The Attempt at a Solution Characteristic equations are: \frac{dx}{x} = \frac{dy}{y^2+1} =...
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    2nd order partial differential equation

    Thanks Mute So then my integrating factor should be e^{-xy} right? Then I have V = e^{xy}[\int e^{-xy}e^x + f(y)] V = e^{xy}[e^{1-y} \int e^x + f(y)] V = e^{xy}[e^{1-y}e^x + f(y)] V = e^{xy+x-y+1} + e^{xy}f(y) U_y = e^{(x-1)y+x+1} + e^{xy}f(y) And I was thinking I...
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    2nd order partial differential equation

    Hello all, this is my first post and I'm having trouble with some homework. Here is the problem: Solve: U_x_y - yU_y = e^x I tried subbing V = U_y then I have V_x - yV = e^x I solve this as a linear equation with an integrating factor of e^{-\frac{1}{2}y^2} and get V =...