Recent content by poso

Heating the container from the bottom will drive a flow of gas inside the container. You might call this a flow occurring due to natural convection. There is only flow possible if there are pressure gradients inside your container. If the driving (bottom) temperature is very high and the top of...

5x4.2x0.40 divided by0.801 = 10.48for 30 You have inserted 4.2 of what excatly for the density? Please refer to Wiki for a proper definition of the dimensionless Re-number. In units: (m/sec * kg/m^3 * m) / (kg/m*sec) = kg*m/sec / (kg/m*sec) = [-] unitless Check your answer using this...

I learned 2300 whas the dividing line but 2000 might just be another good guide value. From what I see in your calculation of the Reynolds number you seem to have multiplied 5 C * 4.2 kJ/kg*K to calculate the fluid flow in meters/sec ? Check the units

I can see a practical reason why my earlier question on the level of fluid in the container was irrelevant. The critical temperature for methane is 190 K and the critical pressure is 45 bar. It would seem that the storing conditions you mentioned at 50 and 100 bar and 300 K define the enclosed...

Be sure to take points in the straightline section of the curves. This is where the definition Youngs modulus = dStress/dStrain is defined. I cannot see you have taken the correct points. Be sure to claculate strain with respect to its original length.

I do not understand how you can solve anything if in the initial statement the initial ratio of liquid to gas is not defined.

In your problem statement you state a constant decelaration of 6 m/s^2 Then you go on with: a = dv/dt = (-6t), which is the correct definition Integration produces : v = -3*t^2+v0. You got the integration idea very right. t = 3 sec. So, continue with: v = ds/dt in a similar way. v = ds/dt...

Ln2 is really cold, -200 C, as was expressed already in the thread comments. Imagine you have closed down your computer to a powerless state. Then you'll have to keep the Ln2 cold, that is in its liquid state. If the Ln2 changes to its gaseous state as a result of not cooling it anymore the...

I suppose a real experiment would not be difficult to set up: pressurized reservoir, small orifice and weighing scale (to measure output flow) On the other hand, there must have been done extensive research on flow of viscous substances through small holes if one considers automated dispensers...

You might consider the type of flow to be expected for oil flowing through the small diameter hole using the definition of Reynolds number and the physical properties of the type of oil considered. If Re < 2300 flow is laminar, above it is expected to be turbulent. Go on from this point.