Recent content by Prabin Acharya

  1. Prabin Acharya

    Angular velocity of an oxygen molecule.

    I don't know if this is the way...but I kind of got the close answer.... we have d = 1.2 × 10^-10 r = d/2 = 0.6 × 10 ^-10 v = 460 3 × rotational KE = 2 × translational KE (3 . I . w^2 ) / 2 = (2 . m . v^2) / 2 3 . m . r^2 . w^2 = 2 . m . v^2 w^2 = (2/3) . v^2/r^2 w = ✓(2/3) . v/r w = ✓(2/3) ...
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