Recent content by PreetiM

For a) I did what a peer tutor told me to do, he said Initial Kinetic energy - work done by friction = final kinetic energy. So I did, .5mvi2 - Ffrictiond = .5mvf2 When I solved for vi I got 202.089 m/s. I admit for part c) I did just guess :(.

Hello! Thanks for helping :) So for part b) I used Fd= 1/2mvi2-1/2mvf2 and for the velocity of the block I got 1.714 m/s. For part c) I just subtracted the final kinetic energy from the initial kinetic energy and got 2.94. I think that looks correct :P.

Homework Statement A .007 kg bullet is fired into a 2 kg wooden block initially at rest on a level surface. The bullet passes through the block and emerges with the velocity of 200 m/s. The block slides .5 m and stops. If the coefficient of the friction between the block and and the surface...